\( \def\dfrac#1#2{\displaystyle\frac{#1}{#2}} \def\solve#1{\begin{array}{rcl}#1\end{array} } \)

Home / A1 Algebraic Techniques / E5 Solving Equation From Graph Part 1

Determine the equation of the line in the graph. The other curve is  \(y=\dfrac{{3}}{{32}}x^3+\dfrac{{5}}{{16}}x^2\)


Solution: Since we do not know what the \(b\) value is, we need to determine the slope in terms of \(b\):

\[ \solve{ m&=&\dfrac{2-b}{2-0}\\ m&=&\dfrac{2-b}{{2}} } \]

Then, we can use the Point-Slope form of a line to get the equation:

\[ \solve{y&=&m(x-x_1)+y_1\\y&=&\dfrac{2-b}{{2}}(x-2)+2} \]